can you explain this code pleeease

Question

#include <iostream>
#include <string>
using namespace std;

class myClass {
public:
string name;
};

int main() {
myClass myObj;
myObj.name = "SoloLearn";
cout << myObj.name;
return 0;
}

//Outputs "SoloLearn"

my doubts are what
name,string and #include<string>do?
----
cant I do this

#include <iostream>
#include <string>
using namespace std;

class myClass {
public:
void name (string name)
cout<< name;

};

int main() {
myClass myObj;
myObj.name(solo learn);
return 0;
}

Answer 1

* string -> It's a variable's data type, an ordered sequence of characters.
* name -> It's the name assigned to the variable type string.
* #include<string> -> It's a library, you need to include the <string> library to use the string data type. Alternatively, you can use a library that includes the string library, for example, #include <iostream>, so you can remove #include <string> from this code.

The second code has some errors:
* void name (string name) -> the code of a method has to be enclosed in Curly Bracket {}.
* myObj.name(solo learn); -> a string has to be enclosed in double quotation marks. myObj.name("solo learn");

Correct code:

#include <iostream>
#include <string>
using namespace std;

class myClass {
public:
void name (string name){
cout<< name;
}

};

int main() {
myClass myObj;
myObj.name("solo learn");
return 0;
}

Answer 2

If you do not know what class field nor string is, I'd refer you to C++ tutorials is this app.