Answer 1

#include <iostream>
using namespace std;

// other way around, I was wrong
bool odd(const char x)
{
return x%2;
}

int main()
{
char c = 23;

if (odd(c))
cout << "odd";
else
cout << "even";
}

Answer 2

if (n%2 == 0)
; //even
else
; //odd n%2 == 1

Answer 3

char is a form of int so this works for it too

Answer 4

char n = '7';
if (n%2 == 0) // perfectly legal
n = 5;

Answer 5

bool even(const char x)
{
return x%2;
}

bool odd(const char x)
{
return !even(x)
}

Answer 6

Cool, so it's solved.

Answer 7

bool even(int x)
{
return x%2;
}

Is this what you need?

Answer 8

Do you want to check if a char is even or odd?

Answer 9

Is if-else really required?