What will be printed after the code run?

Question

https://code.sololearn.com/cNpsoLJluNob/?ref=app

Answer 1

that's ok, thanks

Answer 2

answer without run;)

Answer 3

Is this a challenge or do you need help?

Answer 4

sorry, i don't know how do the challenge...

Answer 5

? Just click the run button.

Answer 6

It's 12 ({1,2}) because a is static. This means, it's a global variable which can only be accessed within the function. I believe it's constructed with the first call.

Answer 7

Did you understand the code with my explanation?

Answer 8

Anyways, here is a detailed explanation (already did the work):

#include <iostream>
using namespace std;

class A
{
public:
void test()
{
static int a = 0; // static: not object dependent, stays forever.
cout << ++a; // equivalent to: a = a + 1; cout << a;
}
};

int main() {
A a;
A b;
a.test(); // Output: 1 (0 + 1)
b.test(); // Output: 12 (1 and 1 + 1)
}