F&A Diskussionen
If: else:
2 Stimmen
2 Antworten
else: invalid syntax
0 Stimmen
3 Antworten
else: Inavlid Syntax!
0 Stimmen
3 Antworten
else: Syntax error
1 Stimme
2 Antworten
It shows syntax error in else:
0 Stimmen
2 Antworten
If and Else: basic code problem
0 Stimmen
1 Antworta = 2
if a == 1:
print("one")
else:
if a == 2:
print("two")
else:
if a == 3:
print("ok")
-2 Stimmen
6 Antworten
l1=[10,20,30]
l2=[10,20,30,40,50]
if l1 in l2:
print("True")
else:
print("False")
0 Stimmen
1 Antwort
Consider the following function fdef f(m): if m == 0: return(1) else: return(m*f(m-1))
3 Stimmen
7 Antworten
def power(x, y):
if y == 0:
return 1
else:
return x * power(x, y-1)
print(power(2, 3))
2 Stimmen
9 Antworten
password = input("your")
if password == "PKMKB" :
print("Access Granted")
else:
print("Access Denied")
0 Stimmen
5 Antworten
def convert(num):
if num == 0:
return 0
else:
return (num % 2 + 10 * convert(num // 2))
5 Stimmen
13 Antworten
def factorial(x):
if x == 1:
return 1
else:
return x * factorial(x-1)
print(factorial(5))
0 Stimmen
4 Antworten
num=20
if num%2=0:
print ("number is even")
else:
if num%2=1:
print ("number is odd")
1 Stimme
6 Antworten
def my_func(n,i,c):
if i==0:
if c==2:
return True
else:
return False
if n%i==0:
c=c+1
return n,i-1,c
n=int(input())
ans=my_func(n,n,0)
if ans==True:
print ("prime")
else:
print('not prime')
0 Stimmen
1 Antwort
What is the largest number this code prints? for i in range(10): if i > 5: print(i) break else: print("7")
4 Stimmen
8 Antworten
print "Enter quantity"
quantity = input()
if quantity*100 > 1000:
print "Cost is",((quantity*100)-(.1*quantity*100))
else:
p
0 Stimmen
4 Antworten
Consider the following function fdef f(m): if m == 0: return(1) else: return(m*f(m-1)) Which of the following is correct?
0 Stimmen
10 Antworten
m = (float(int("please put numbers")))
x=0
if x<=m:
print (x)
x+=2
else:
print("exit")infinite loop what is wrong
0 Stimmen
10 Antworten
def fb(n):
if n==0:
return 0
if n==1:
return 1
else:
return(fb(n-1)+fb(n-2))
print
1 Stimme
1 Antwort
print('Hello world!')
x = 1
while x < 10:
if x%2 == 0:
print(str(x) + " is even")
else:
print(str(x) + " is odd")
0 Stimmen
2 Antworten
num = int(input())
def fibonacci(n):
if n==1:
return 0
elif n==2:
return 1
else:
return fibonacci (n-1) + fibonacci (
1 Stimme
7 Antworten
x = 1
while x < 10:
if x%2 == 0:
print(str(x) + " is even")
else:
print(str(x) + " is odd")
elif:
3 Stimmen
7 AntwortenWhy does this not work?
x = input("")
if x==potato:
print("YOU SIR, ARE AMAZING")
else:
print("WHY...")
0 Stimmen
3 Antworten
nums = [1, 2, 3,5]
nums(1)=nums(2)-0
if 2 in nums:
nums.append 8
print(nums)
else:
nums.append(5)
print(nums)
print(nums)
0 Stimmen
4 Antworten
Can someone explain this, def fib(x): if x==1 or x==0 return 1 else: return fib(x-1) + fib(x-2)
0 Stimmen
2 Antworten
siblings = int(input())
popsicles = int(input())
#your code goes here
if popsicles % 2 == 0:
print("give away")
else:
0 Stimmen
2 Antworten
Rearrange the code to print "Welcome" if the script is imported, and "Hi" if it is not imported. print("Welcome") else: p
-2 Stimmen
5 Antworten
binary = "1010"
flip = ""
for i in binary:
if i == "0":
flip+ = "1"
else:
flip+="0"
print(flip)
#output:0101
# please exp
0 Stimmen
6 Antworten
Heute heiß
Question
4 Votes
overloading operators << >>
1 Votes
I dont now that how to do js
2 Votes
fully dynamic arrays
1 Votes
Wishkit alternative for android
1 Votes
How to start in web dev?
0 Votes
Hi
0 Votes
Issue in code
0 Votes