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can someone help solve this:what is the output of this;
class A {
public:
A () { cout << "a";}
~A () { cout << "b" ;}
};
class B
public:
B () { cout << "c" ;}
~B () {cout << "d" }
};
int main () {
B b
A a
};
1 Stimme
3 Antworten
So i wanted to make a calculator so i did int << a = 5; int << b = 10; int sum a + b = 15; but it didnt work
0 Stimmen
1 Antwort
int a = 14;int b = 23; if (a&& b) cout << a; else cout << b; can some body tell my what will be the output and explain pl
1 Stimme
15 Antworten
#include <iostream>
using namespace std;
void test(int*, int*);
int main() {
int a = 5, b = 5;
cout << "Before changing:" <
-1 Stimme
2 Antworten
int a =10
int b = 2
a*=b
cout << a/ ++b
What is the output? And how do you derive it? Appreciate the help! Thanks!
0 Stimmen
9 Antworten
How do we arrive at 26 as answer here?
int a = 10;
int b = 13;
int *p1= &a;
int *p2= &a;
*p1 = b;
cout << (*p1) + (*p2);
7 Stimmen
6 Antworten
#include <iostream>
using namespace std;
int sum(int a, int b=42) {
int result = a + b;
return (result);
}
int main() {
int x = 24;
int y = 36;
//calling the function with both parameters
int result = sum(x, y);
cout << result << endl;
//calling the function without b
result = sum(x);
cout << result << endl;
return 0;
}
why is da last function cout 66 and not 48 isn't it suppose to add 24+24?
1 Stimme
6 Antworten
what is tjis code problem!
#include <iostream>
using namespace std;
int main()
{
int b = 5;
int arr[b] = {11, 35, 62, 555, 989};
int sum = 0;
for (int x = 0; x < 5; x++) {
sum += arr[x];
}
cout << sum << endl;
return 0;
}
I cannot make an array using int variable in order to define array's element number!?
1 Stimme
7 Antworten
Wher is mistake?
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5 Antworten
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