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good coders i need ur help plz.
in my assignment there is this tricky question.
write a program to calculate sum of the series: 1 - 1/2 + 1/3 -1/4 +..... -n
until the term that is less than 0.0001(1/10000) is reached.
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3 Antworten
why does this code output that there is an error because the else statement doesn't have a corresponding if statement?. How do i correct this?
#include <iostream>
using namespace std;
int main() {
int a;
for (int x =0; x<5;x++){
cin>>a;
if (a<1){
cout<<"a cannot be less than 1\n";
}
else if (a>10){
cout <<"a cannot be greater than 10\n";
}
}
else{
cout<<"code can run now"<<endl;
}
return 0;
}
3 Stimmen
8 Antworten
can someone kindly correct me if i am wrong about this quote "As the program contains multiple lines of code, you should create it as a separate file and run it."
does that mean that if my code gets bigger it is advisable to create less line of codes but many files?
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Web-Dev-Kit V-2.0.0
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1 Antworti want to write a line of code that looks like this
if (a>10){
I know that in c++, you cannot just have greater than (>) or less than (<). j
it must be (>=) or (<=). But the code I need to write does not include the equal to(=). it just has to be greater than 10. What do I do?
1 Stimme
2 Antwortencan someone tell me how to make it impossible for a user to type a 'userchoice1[x]' value that does not range from 1 - 10.
If you also know a way I can make the user input another value for the 'userchoice1[x]' variable if it is less than 1, I'll appreciate you share the knowledge with me.
please see the short code below
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2 AntwortenHeute heiß
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