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How do I to round float result?

I Will calculate 10 / 3, and result is 3.333333333 I want To round this result into 3 number, so The result should be 3.333 So, how I do it?

7th Nov 2016, 1:26 AM
Fendi Septiawan
Fendi Septiawan - avatar
3 Antworten
+ 2
if you want to print this result, rounding float to certain decimal points, do this: x == 10/3 print("{0:.3f}".format(x)) that would output your number limiting it to 3 signs after a dot
7th Nov 2016, 5:16 AM
Demeth
Demeth - avatar
+ 1
def round(num): if (num + 0.5) % 2 == 0: print (num + 0.5) elif (num + 0.4) % 2 == 0: print(num + 0.4) elif (num + 0.3) % 2 == 0: print (num + 0.3) elif (num + 0.2) % 2 == 0: print (num + 0.2) elif (num + 0.1) % 2 == 0: print (num + 0.1) else: print(int(num)) round(5.3) round(5.5) This works but is a little enefficient. Output: 5 6
7th Nov 2016, 2:04 AM
Avery
Avery - avatar
+ 1
x = 10/3.0 round (x , 3) # Or in one step round (10/3.0 , 3)
7th Nov 2016, 3:26 PM
Chris
Chris - avatar