+ 2
Could someone explain why it is showed "1" in Java?
int x = 1; x = x++; System.out.println(x);//the issue
4 Antworten
+ 10
x does get incremented, but not after x is assigned its old value
+ 4
What the code thinks:
1) Oh so now we have a somebody called x
2) Okay there is an x with a value of x, or 1
3) okay increment the first x and forget it
4) print out the x that we have now
x++ alone will ddo what you want don't need to declqre x=x++
+ 2
When using increments You have to think about how You want to do the incrementation. There're two possibilities. First one is increment the number before execution by ++x which leads to x= 2, or increment after execution by x++ which leads to x = 1 and x = 2 after execution.
+ 1
Try ++x