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# I tried asking AI but AI just couldn't get the correct answer to the code below

Why does the code below output 3? def rec(n): n %= 5 if n <= 1: return n else: return rec(n - 1) + rec(n - 2) print(rec(9))

12th Apr 2024, 4:55 PM
eMBee
3 Antworten
+ 4
The code outputs 3 because the recursion function rec(n) is calculating the Fibonacci sequence modulo 5. When rec(9) is called, the function will first calculate 9 % 5 = 4. Since n = 4 is not less than or equal to 1, the function will make two recursive calls rec(4 - 1) & rec(4 - 2). For rec(3) [ from the first recursive call ], it calculates 3 % 5 = 3 which is greater than 1, so it again makes two more recursive calls. For rec(2) & rec(1), which then return 2 & 1 respectively. These values are added together in the recursion tree to get the final result: 2 + 1 = 3, which is output as the result of rec(9). Actually the function calculates the Fibonacci sequence modulo 5, leading to the output of 3 for rec(9).
12th Apr 2024, 5:37 PM
`нттየ⁴⁰⁶
+ 2
In such as situations you can analyze what happend in a code in a debug editor. Another way if you do not have that is to use the print statement how I present in thi example: loop=0 def rec(n): global loop loop += 1 print(f'loop={loop}') print(f'input n={n}') n %= 5 print(f'after % n={n}') if n <= 1: print(f'n<=1: n={n}\n') return n else: print(f'else: n={n}\n') return rec(n - 1) + rec(n - 2) print(rec(9)) https://sololearn.com/compiler-playground/cBz1F82S0P1o/?ref=app
12th Apr 2024, 9:20 PM
JaScript
0
def rec(n): if n <= 1: return n else: return rec(n - 1) + rec(n - 2) print(rec(9))
14th Apr 2024, 2:40 AM
Vidhya Tharan