what is the output of this code? Here is asking for the argument.. how can it be false the first one?

Question

what is the output of this code?
var arr1 = [1,2,3];
var arr2 = [1,2,3];
var arr3 = arr1;
console.log(arr1==arr2);
console.log(arr1==arr3);

/* Showing the result as 'false true', why?

Answer 1

assuming you are talking about Javascript, you should mostly use ===

Array equality is tricky, though...

https://flexiple.com/javascript/javascript-array-equality/

https://stackoverflow.com/questions/7837456/how-to-compare-arrays-in-javascript

Answer 2

In the first comparison, arr1 and arr2 are being compared using the == operator, which compares their values rather than their references. Since arr1 and arr2 are distinct arrays with the same elements, they are considered equal in value, but not equal in reference. Therefore, the comparison evaluates to false.

In the second comparison, arr1 and arr3 are also being compared using the == operator. However, in this case arr3 is assigned the value of arr1, so they both refer to the same array in memory. Therefore, the comparison evaluates to true.

Answer 3

From what I understood:
arr1 == arr3 will return true because arr3 and arr1 points to same object

And arr1 == arr2 returns false because they point to different objects (even though both arrays have the same content, still they're different)