It still show me 1 error

Question

import java.util.Scanner;

//your code goes here
public class Converter{
static int toBinary (){
String binary="";
int num;
while (y>0){
binary = (y%2)+binary;
y/=2;
return num;
}
}
}
public class Program {
public static void main(String[ ] args) {
Scanner sc = new Scanner(System.in);
int x = sc.nextInt();
int x == int y;
System.out.print(Converter.toBinary(x));
}
}

Answer 1

You can continue in your last same post.. Why you need another dublicates one..? if it not helped, then you can delete one.., to avoid dublicates..
int x == int y ; is invalid statement..
**read about variable and its initialization a bit more..
You are passing x to toBinary method but not catching it..
For => toBinary(x) , the method definition must be like
toBinary (int y) { // you are using y , so
..
}
Not toBinary() {
..
}

**read about methods in java..
**read about return in method..

You have logic flaws also..
So before attempting, a bit more revise the topics..
You need to see some example, how to write correct syntax and logic..

https://www.sololearn.com/discuss/3055447/?ref=app