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What is wrong with this code
My if statement doesn't evaluate to be true hence the print statement doesn't run. The goes the code. contacts = [ ('James', 42), ('Amy', 24), ('John', 31), ('Amanda', 63), ('Bob', 18) ] #print(contacts.get(input(,'not found')) x = input() if x in contacts: print (x+'is' + contacts[x][1]) else: print( 'not found')
6 Antworten
+ 2
Is that how the original code look like? is the <contacts> not a dictionary?
+ 1
The contact is a list which has tuples in them. So yes; that is how the original code looks like
+ 1
Gemuh Hans First, You need to take input in integer as your searchup is going to be with 42,24,31... which is in integer.
Second, You can iterate over contacts and every iteration will give you one tuple having name and number,
Now, you have to check if the number you searching is in that tuple or not.
You can simply do..
eg. 42 in x (it's a tuple)
If found you have to print it out and flag it as True.
Outside the for loop, check if flag is true or false.
If false it means no data found.
contacts = [
('James', 42),
('Amy', 24),
('John', 31),
('Amanda', 63),
('Bob', 18)
]
n = int(input())
m = False
for x in contacts:
if n in x:
print('{} is {}'.format(n, x[0]))
m = True
break
if m != True:
print("Not found!")
+ 1
Thanks so much
0
Here you see an `else` block underneath the `for...in` block we use to iterate the <contacts> `list`.
The `else` block is placed at the same indentation level to that of the `for...in` loop, and it will only be processed IF the loop finishes completely.
When the `break` statement is issued (loop exits normally, not from issuing `break` statement), the `else` block underneath the `for...in` block will not be processed.
x = input()
for contact in contacts:
if x in contact:
print( x, 'is', contact[1] )
break
else:
print( 'Not found' )
P.S. Also, if this was a task/coach, do pay attention on what to print, different letter case of output is one major factor that failed some people, as I have read ...
0
Can you please add Python in the tags above where you wrote 'contactsearch' ☝
Example:
python contact-search 👍