Can you help me with a simple solution for my homework in python?

Question

I have to generate X_NNNN_YY as
“X” have to be the letter “P”
“ _ “ have to be space
“NNNN” have to be four numbers between (0,9) and the whole 4-digit number can be divided by 6
“_” must be space
“YY” have to be two letters between this list [‘A’, ‘B’, ‘C’, ‘E’]

JUST DID THIS BUT IT’S NOT EXACTLY WHAT I AM LOOKING FOR:

alphabets=[‘A’, ‘B’, ‘C’, ‘E’]

Numbers = [chr(i) for i in range(org(‘0’), ord(‘9’)+1)]

Combinations=[one + two + three + four + five + six for one in Numbers for two in Numbers for three in Numbers for four in Numbers for five in alphabets for six in alphabets]

print(Combinations)

I’m new at python and I will be very grateful If you suggest some ideas 😇

Answer 1

from itertools import combinations_with_replacement as cwr

lst = ['P '+str(n).zfill(4) for n in range(0,10000,6)]
cmb = [*cwr('ABCDE',2)]
cmb = [s+' '+a+b for s in lst for a,b in cmb]

print('\n'.join(cmb))

# reach timeout limit before print ends in code playground ^^

Answer 2

give it a try first, then ask for help.

https://www.sololearn.com/discuss/1316935/?ref=app

Answer 3

You’re very close! You don’t need to manually build every digit or character.
Since the required format is: P NNNN YY

Here is the sample solution you can follow by the way :

alphabets = ['A', 'B', 'C', 'E']

results = []

for num in range(0, 10000): # 0000 to 9999
if num % 6 == 0: # must be divisible by 6
four_digits = f"{num:04d}" # format as 4-digit string

for first in alphabets:
for second in alphabets:
code = f"P {four_digits} {first}{second}"
results.append(code)

for r in results:
print(r)