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Using dictionary comprehensions in functions

I'm trying to use dict comprehensions to define an occurrence function that counts how many times a character shows up in a string. The resulting dict should be made of (character : occurence), however in my case all the values are 1, any help ? The code below contains an occurence function defined the normal way, and a oneliner which doesn't work yet (occurrence_one) https://code.sololearn.com/c25wjc9yTBcZ/?ref=app

4th May 2018, 4:25 PM
Younes L.
Younes L. - avatar
4 Antworten
0
'''Younes L. you never defined the that count is anathema. But why not I'm up for the challenge. try this. ''' def oc(s): return({i:len(list(filter(lambda x:x==i,s))) for i in set(s)}) print(oc('aaaabbaccac'))
4th May 2018, 8:01 PM
Louis
Louis - avatar
+ 1
''' Jan Markus has a point, but I assume you want to understand dict comprehension. this is how I would do it. ''' def oc(s): return({i:s.count(i) for i in set(s)}) print(oc('aaaabbaccac'))
4th May 2018, 6:27 PM
Louis
Louis - avatar
0
thanks Louis , Jan Markus , but isn't there a way without the count function ?
4th May 2018, 7:21 PM
Younes L.
Younes L. - avatar
0
Louis len is definitely a more straightforward approach than sum , thanks ! do you have any idea what makes my occurrence_one always return 1 as values for the returned dictionary... apart from being named occurrence_one, of course 😂 in the article I linked in the code, it says dictionaries can eventually be used as alternative to lambda functions (kind of what I'm trying to achieve here)
4th May 2018, 8:07 PM
Younes L.
Younes L. - avatar