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java value types

Why its 5? Can you please explain for me? public class MyClass { public static void main(String[ ] args) { int x = 5; addOneTo(x); System.out.println(x); } static void addOneTo(int num) { num = num + 1; } } // Outputs "5"

29th Nov 2016, 6:54 PM
Gaye
3 Antworten
+ 3
Functions arguments are passed by value, so when addOneTo increments 'num', in fact, it doesn't increment the actual value of 'x'. It remains unchanged, so the output is 5.
29th Nov 2016, 7:02 PM
Álvaro
+ 3
this returns to "pass by value" subject in java fundamentals concepts, that is when you pass a variable to a method, just a copy of that variable passed to the method and the variable doesn't change after runing the method ;) read more about this!
29th Nov 2016, 7:05 PM
Nima Moradi
Nima Moradi - avatar
0
the variable you set in MyClass is 'x' is passed through addOneTo but it's a local variable there. Also inside addOneTo method 'num' variable is local variable there and after increased to 6 it will be destroyed since there isn't any return value.
29th Nov 2016, 7:40 PM
Aliakbar Rezapour
Aliakbar Rezapour - avatar