Q&A Discussions

Why output of this code is:5 9 #include<stdio.h> int main() { char s[] = "Hello\0Hi"; printf("%d %d", strlen(s), sizeof(s)); }

unary operators : If float x; then x=sizeof(double) then why out is 0

printf("float: %ld \n", sizeof(float));. why we put :%ld\n after float

How can I get array size in function call? 010000110010101100101011

Why sizeOf(double) == sizeOf(long double)?

Int main(){int a; a=31&14+5*sizeof(6.4);printf("%d",a) } output=2 how?????

About size int in C

Why we write "sizeof" is that important

Why we write "sizeof"

C - Why "a" has the size of an int?

I can't understand the sizeof in C

find output with reason:- main() { if(sizeof(int)>-1) printf("Hello"); else printf("Hii") }

Why is the size of an empty class 1 byte?

How we use sizeof in string?

What is the warning produced for "sizeof(int)"

What is the difference between sizeof() and strlen()

sizeof() varies with compilers (or systems)?

struct node{ int x; node* n} int main(){ cout<<sizeof(node) };

Why is the sizeof(v) showing 4 bytes??

Sizeof