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Isn't the line 1 and line 4 means the same that is in *ptr and hello both contain manash so why hello runs but *ptr doesn't?
0 Votes
4 Answers
#include<stdio.h> int main() { char *ptr = "Hello"; printf("%c\n", *&*ptr); return 0; }
0 Votes
1 Answer
Why mostly in c program using pointer pointer is daclared in this way ? *ptr = NULL
1 Vote
4 Answers
The output is 55, but I don't understand why the memory address of the *ptr is 23fe3c.
1 Vote
5 Answers
What's the difference between this {MyClass obj;
MyClass *ptr = &obj;} and this {Myclass *ptr=new Myclass}?....
2 Votes
1 Answer
#include <iostream>
using namespace std;
int main() {
int x=10,y=20;
int *ptr = &x;
int &ref= y;
*ptr++;
ref++;
cout<<x<<y
0 Votes
9 Answers
But *ptr stores the actual value of the varible x right? Then why is it written *ptr=&x when it does not store its address.
2 Votes
3 Answers
what is the output of following program
type def int integer
# define int chat
void main ()
{ int i= 65;
int *ptr = &i;
int *j =
-1 Vote
10 Answers
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