How to compare 2 strings?

Answer 1

String fooString1 = new String("foo");
String fooString2 = new String("foo"); // Evaluates to false
fooString1 == fooString2; // Evaluates to true fooString1.equals(fooString2); // Evaluates to true, because Java uses the same object
"bar" == "bar";
or
String nullString1 = null;
String nullString2 = null; // Evaluates to true nullString1 == nullString2; // Throws an Exception nullString1.equals(nullString2);
== handles null strings fine, but calling .equals() from a null string will cause an exception:

Answer 2

1) String comparison using equals method
2) String comparison using equalsIgnoreCase method
3) String comparison using compareTo method
4) String comparison using comp
public class StringComparisonExample {
    public static void main(String args[]) {
        String tv = "Bravia";
        String television = "Bravia";
        // String compare example using equals
        if (tv.equals(television)) {
            System.out.println("Both tv and television contains same letters and equal by equals method of String");
        }
        // String compare example in java using compareTo
        if (tv.compareTo(television) == 0) {
            System.out.println("Both tv and television are equal using compareTo method of String");
        }
        television = "BRAVIA";
        // Java String comparison example using equalsIgnoreCase
        if (tv.equalsIgnoreCase(television)){
            System.out.println("tv and television are equal by equalsIgnoreCase method of String");
        }
        // String comparison example in java using CompareToIgnoreCase
        if(tv.compareToIgnoreCase(television) == 0) {
            System.out.println("tv and television are same by compareToIgnoreCase of String");
        }
        String sony = "Sony";
        String samsung = "Samsung";
        // lexicographical comparison of String in Java with ComapreTo
        if (sony.compareTo(samsung) > 0) {
            System.out.println("Sony comes after Samsung in lexicographical order");
        } else if (sony.compareTo(samsung) <0) {
            System.out.println("Sony comes before Samsung in lexicographical order");
        }
    }
}

Answer 3

in c++,if there are 2 strings ,each of equal length,
int temp=0;
if(strlen(str1)==strlen(str2))
{ for(int i=0;str[i]!="\n";++i)
{ if(str1[i]!=str2[i])
temp=-1;
}
}
if(temp==0)
cout<<"\nStrings are equal";