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# in place operators

I do not understand how this code work? X=2 X+=3 print (X) The answer is 5!

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Please, help, how I can to do the project number 18??? calculator?

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the better way to write it is the next x = 5 x += 3 is the same to x = x + 3 print(x)

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This operator is called as compound assignment operator , it increases the readability of the code. This operator adds the value with the variable which is on the LHS which is nothing but x = x +3

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Here first the value of X is assigning with the value 2. The next line it is in assignment operator (eg:X+=2 i.e X=X+2) so,X is 2 ,adding 3 to it so the answer is 5 then print the X valuee

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X = 2 X+=3(it means X = X +3, X = 2 + 3, X = 5)

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X=2 is assigning the value of 2 to the variable X.. The next line is adding 3 to the variable X. Since X is = 2, adding 3 to it makes 5.

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This is a very strange way of writing.

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X+=3 It simply means X=X+3

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x+3=5 is also we right x+=3

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Your code: X=2 X=X+3 print(X) Console: 1)X:2 2)now X:5 3)show X(5) to user

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X takes value 2 and it us added to 3 which gives 5(2+3)

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The first assignment of x is 2 then the second assignment of x take 2 from the first assignment of x and then adds 3 to it meaning that 2+3=5

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Here, initially X is assigned with 2 i.e (X=2) According to assignment operators The expression X+=3 is equal to X=X+3 substitute x=2 which is initially assigned Now X= 2+3 = 5 Hope that this will help :)

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Given code X = 5; X+=3; We know X = 5; Then (X = X+3) So print(x)

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X+=2 is considered as x=x+2

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x += 3 interchangeable with x = x + 3

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Compute X=9 Print (x) X *=3 Print (x)