1 13 135 1357 ....... ...... ......... n lines

Answer 1

//example n = 17
void odd(int n)
{
int oddNr = 1;
for(int c = 1 ; c <= n ; ++c)
{ cout<<oddNr;
oddNr += 2;
}
cout<<endl;
}
int main()
{
for(int x = 1 ; x <= 17; x++)
{
odd(x);
}
return 0;
}

Answer 2

Ah, you wanted a nested loop
in that case, for n = 10 lines:
int main()
{
for(int i = 1 ; i <= 10 ; i++)
{
int odd = 1;
for(int j = 1 ; j <= i; j++)
{
cout<<odd;
odd += 2;
}
cout<<endl;
}
return 0;
}