The average of 20 numbers is zero. Of them, at the most, how many may be greater than zero?

Question

A. 0
B. 1
C. 10
D. 19

Answer 1

@ChaoticDawg is correct.

Answer 2

D 19
if -19 was 1 number and the rest of the numbers were 1
1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + -19 = 0
0/20 = 0

Answer 3

Your answer is right but your logic is not right Dude !

Answer 4

Can you tell me Which Logic are you applying ???

Answer 5

20+20+20+20+20-20-20-20-20-20 = 0
avg=0/20;
avg=0

Answer 6

The Exact Explanation:
Average of 20 numbers = 0.
Sum of 20 numbers (0 x 20) = 0.
It is quite possible that 19 of these numbers may be positive and if their sum is a then 20th number is (-a)

Answer 7

ans is 19
take any 19 numbers and add them. let the sum of those numbers be x. let the 20th number be -x. so when you find the AVG of 20 Numbers it will be 0