Answer 1

What Deep said.
def pat(n):
for i in range(0,n):
for j in range(0,n):
print(n)
print("\r")
n=int(input())
pat(n)

BTW a couple of streamlining points - since 0 is the default start for range(), all you need to say is 'range(n)'. Also, since print() automatically ends with a carriage return (unless you tell it to end with something else using end=), you don't need the "\r" - just 'print()' does the same thing.

Answer 2

This works. There may be a shorter way to do it but I couldn't think of one 🙂

def pat(n):

if n>0 and n<=1000:

for i in range(n):
p=1
for j in range(n):
if j < n - 1:
print(p, end='_')
else:
print(p, end='')
p=p+1
print()

n=int(input())
pat(n)

Answer 3

Check David's Code. That's what I meant.
First accept the value of 'n', and then pass it into the function.

Answer 4

Buddy, you gotta follow the special rule of Python.
Check this out.

def add(a, b):
print("Addition of given numbers: ")
print(a+b)

add(3,5)
add(2,2)

#See that gap? Intended space. Python needs to #know which statement belongs to which function. #Hope you get it. Otherwise I'll show you an another #example.

Answer 5

Bro, you need to accept the value of 'n' to pass that as a parameter, right?
But you'd write that unit inside the function.
Write outside the function and pass it as a parameter.