Why does this output an error?

Question

Code:
#include <cassert>
#include <cctype>
#include <climits>
#include <cmath>
#include <cstdio>
#include <cstdlib>
#include <cstring>
#include <ctime>
#include <limits>
#include <string>
#include <iostream>
#include <sstream>
#include <functional>
#include <algorithm>
#include <bitset>
#include <deque>
#include <list>
#include <map>
#include <queue>
#include <set>
#include <stack>
#include <vector>
#include <system_error>
#include <string>
using namespace std;
int add(int c1, int c2)
int sos = c1+c2
return sos;
int main(){
for(a1=5 a1<=67 a+=7)
cout<<"___________________\n============="
string scan = "dfig.res.error"
int n1 = 16;
float n2 = 54.541;
cout<<"Please enter two numbers and a symbol\n";
int a;
int b;
int c;
int d;
int e;
int f;
int x;
int y;
int z;
int w;
int r;
char sym; //operator
char is = '='
cin>>a;
cin>>sym;
cin>>b;
cin>>sym;
cin>>c;
cin>>sym;
cin>>d;
cin>>sym;
cin>>e;
cin>>sym;
cin>>f;
cin>>sym;
cin>>x;
cin>>sym;
cin>>y;
cin>>sym;
cin>>z;
cin>>sym;
cin>>w;
cin>>sym;
cin>>r;
switch(1){
case '+':
cout<<a<<'+'<<b<<'+'<<c<<'+'<<d<<'+'<<e<<'+'<<f<<'+'<<x<<'+'<<y<<'+'<<z<<'+'<<w<<'+'<<r<<'='==a+b+c+d+e+f+x+y+z+w+r;
break;
case '-':
cout<<a-b-c-d-e-f-x-y-z-w-r;
break;
case '*':
cout<<a*b*c*d*e*f*x*y*z*w*r;
break;
case '/':
cout<<a/b/c/d/e/f/x/y/z/w/r;
if(a||b||c||d||e||f||x||y||z||w||r==0){
cout<<"UNDEFINED,CANNOT DIVIDE BY 0!";
case '1':
if(a+b){
if(1+1){
cout<<"1+1=2";
}
if(1+2==2+1){
cout<<'1+2=3';
}
if(1+3==3+1){
cout<<'1+3=4';
}
if(1+4==4+1){
cout<<'1+4=5';
}
if(1+5==5+1){
cout<<'1+5=6'
}
if(1+6==6+1){
cout<<'1+6=7'
}
}
}break;
}
return 0;
}
Error:
Compilation error

Answer 1

@mei he is not rude, he's just telling you what's wrong with the code and it can help you to compile this somewhere else than code playground

Answer 2

how could the switch(1) be wrong?
I SAID WHAT DO YOU MEAN!!!!!!!!??????????

Answer 3

AND WHAT NUMBER DO YOU CHOOSE!!!???
1....10

Answer 4

There are various errors: the body of your method add has to be between { and }
the syntax of the for loop os wrong:
for (type name=value;condition;statement){}
would be right so in your case
for (int a1=5;a1 <=67;a1+=7)
cout<<"your text";
you also have to end every statement with ; (semicolon )
e.g
string scan="dfig.res.error";
the switch (1) makes no sense at all.
then the if with the 0 check is wrong:
if (a==0||b==0 ...)
would be right.
If the aim of your code is to make a nice calculator,
google stroustroup (the creator of c++) calculator.

Answer 5

This makes sense:
There are various errors: the body of your method add has to be between { and }
the syntax of the for loop os wrong:
for (type name=value;condition;statement){}
would be right so in your case
for (int a1=5;a1 <=67;a1+=7)
cout<<"your text";
you also have to end every statement with ; (semicolon )
e.g
string scan="dfig.res.error"
This makes no sense:
the switch (1) makes no sense at all.
then the if with the 0 check is wrong:
if (a==0||b==0 ...)
would be right.

Answer 6

如此无礼！
你选择了什么？
1 .... 10
开关（1）如何出错？
我说你是什么意思？
这说得通：
有各种错误：您添加文本的方法必须在{和}之间
for循环错误的语法：
For（type name = value; condition; statement）{}
在你的情况下会是对的
For（int a1 = 5; a1 <= 67; a1 + = 7）
Cout <<“你的话”
你也必须结束每一个陈述; （分号）
例如
String scan =“dfig.res.error”
这个不成立
开关（1）完全没有意义。
那么如果检查与0是错误的：
如果（a == 0 || b == 0 ...）
会是对的
Rúcǐ wú lǐ!
Nǐ xuǎnzéle shénme?
1.... 10
Kāiguān (1) rúhé chūcuò?
Wǒ shuō nǐ shì shénme yìsi?
Zhè shuō dé tōng:
Yǒu gè zhǒng cuòwù: Nín tiānjiā wénběn de fāngfǎ bìxū zài {hé} zhī jiān
for xúnhuán cuòwù de yǔfǎ:
For(type name = value; condition; statement){}
zài nǐ de qíngkuàng xià huì shì duì de
For(int a1 = 5; a1 <= 67; a1 + = 7)
Cout <<“nǐ dehuà”
nǐ yě bìxū jiéshù měi yīgè chénshù; (fēn hào)
lìrú
String scan =“dfig.Res.Error”
zhège bùchénglì
kāiguān (1) wánquán méiyǒu yìyì.
Nàme rúguǒ jiǎnchá yǔ 0 shì cuòwù de:
Rúguǒ (a == 0 || b == 0...)
Huì shì duì de

Answer 7

Then read this!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
如此无礼！
你选择了什么？
1 .... 10
开关（1）如何出错？
我说你是什么意思？
这说得通：
有各种错误：您添加文本的方法必须在{和}之间
for循环错误的语法：
For（type name = value; condition; statement）{}
在你的情况下会是对的
For（int a1 = 5; a1 <= 67; a1 + = 7）
Cout <<“你的话”
你也必须结束每一个陈述; （分号）
例如
String scan =“dfig.res.error”
这个不成立
开关（1）完全没有意义。
那么如果检查与0是错误的：
如果（a == 0 || b == 0 ...）
会是对的
Rúcǐ wú lǐ!
Nǐ xuǎnzéle shénme?
1.... 10
Kāiguān (1) rúhé chūcuò?
Wǒ shuō nǐ shì shénme yìsi?
Zhè shuō dé tōng:
Yǒu gè zhǒng cuòwù: Nín tiānjiā wénběn de fāngfǎ bìxū zài {hé} zhī jiān
for xúnhuán cuòwù de yǔfǎ:
For(type name = value; condition; statement){}
zài nǐ de qíngkuàng xià huì shì duì de
For(int a1 = 5; a1 <= 67; a1 + = 7)
Cout <<“nǐ dehuà”
nǐ yě bìxū jiéshù měi yīgè chénshù; (fēn hào)
lìrú
String scan =“dfig.Res.Error”
zhège bùchénglì
kāiguān (1) wánquán méiyǒu yìyì.
Nàme rúguǒ jiǎnchá yǔ 0 shì cuòwù de:
Rúguǒ (a == 0 || b == 0...)
Huì shì duì de

Answer 8

Also, you misspelled 'is' as 'os'.

Answer 9

And so rude!?

Answer 10

Insulted me...¥:848(,!&9,3¥,83),¥29.)83;¥39:¥3&,0’zwpxkpnigug,’epenpxjwhsiqhxosxgwjdpjp,+{‘,!03!”,!92;¥2)1 the hdeidjowdjoejcojd2’donehfuwb,29