Why cout << (1<<1); print 2?

Question

cout << (1<<1); when run the output is:
2

Answer 1

@Nithiwhat:
You've inverted left and right shift: left multiply and right divide ;P ( think to binary: 00000010 left shift is 00000100, right shift is 00000001 )

Answer 2

specifically a bitwise operator.
here. this might help.
http://www.cplusplus.com/doc/tutorial/operators/

Answer 3

Left shift (<<) operator
Solution:
x << y = x/power(2,y)
1<<1 = 1/power(2,1) = 0
Right shift (>>) operator
Solution:
x >> y = x*power(2,y)
1>>1 = 1*power(2,1) = 2

Answer 4

<< is an operator.

Answer 5

@Nithiwat
I found that << is left shift and >> is right shift.