Error in Program

Question

https://code.sololearn.com/ceN5q84VCiJv/?ref=app
Pls help me, I couldn't get it why this error is coming if anyone has any solution to the error then pls tell me :(

Answer 1

https://code.sololearn.com/cJIt2knE0HQi/?ref=app
I got my solution everyone
When I tried to do it by using io package, it ran perfectly
Stefanoo SoloProg José Ricardo Jiménez Aguilera just check it out

Answer 2

Use
int n= Integer.parseInt(in.nextLine());

instead of
int n=in.nextInt();

Answer 3

If your input is like this it works.
Input:
2 Name1
Name2
Ouput:
N
It's because your a still on the first line after nextInt and nextLine finds a Space as first char.

Answer 4

That's because a String itself can throw this exception.
It's not the array who is throwing it.
And your first string at Index 0 is empty.

Answer 5

You should give a try to your code in a real IDE. If you can't and want to continue here, you should add in.nextLine() before the for loop where you start adding the elements to the array, otherwise it will remain in the same line where the integer was written and the first element of the array will be left empty.
That error was generated because the first element in your array was left empty because when you call in.nextLine() in the first iteration, the "cursor" is still right after the integer and not at the following line as you (and also me) would expect. As the first element of the array was left empty, requesting its first char is impossible and causes an exception.
As a future advice, avoid that kind of error by using the method .isEmpty() before calling any method to handle the value of any String variable

Answer 6

Exception in thread "main" java.lang.StringIndexOutOfBoundsException:

index out of range: 0 at java.base/

java.lang.StringLatin1.charAt(StringLatin1.java:48) at java.base/java.lang.String.charAt(String.java:711) at Program.main(Program.java:18)

I think the main problem is in line 18
Char ch=a[i].charAt(0);
It is saying the index of the string is not 0 or the compiler can't find any character in that position. But as a learner, I know every string starts with a position 0, but why this error is coming everytime I don't know.

Answer 7

Stefanoo sir, I couldn't get it! 😥