Why there is no need of for loop in array with char datatype to get the input

Question

In this program I can just simply name the array with size and get the input.
#include<iostream>
using namespace std;
int main() {
char a[10];
cin>>a;
cout<<a;
return 0;
}
But I case of int variable, why we have to use loop to get the input and output,
#include<iostream>
using namespace std;
int main()
{
int a[5],i;
for(i=0;i<5;i++)
{
cin>>a[i];
}
for(i=0;i<5;i++)
{
cout<<a[i];
}
return 0;
}

Answer 1

Characters arrays are used as strings in C++ and C (there is a string class in C++ too). In a lot of places, you'll see special behaviour of characters arrays because they're treated as strings
In the first code, by taking input into a character array, you're basically taking a string as input, and placing it's characters in your array. This is special behaviour of cin defined for character arrays
It's the same with printing - if you print an integer array, you'll get a pointer in the output, but if you print a character array, the whole array will be printed as a string (till a '\0' is countered)
Again, this behaviour of cout was separately defined for character arrays