Is there any use case for a closure where the inner function doesn't have its own parameter?( Python)

Question

Because I got no replies, I'll try to ask this using snippets:

def f_outer(x):
def f_inner():
return x * 2 # or whatever
return f_inner #

fin = f_inner(5)
print(fin())

Is there any weird chance on Earth for this to be better than

def f_outer(x):
def f_inner():
return x * 2
return f_inner() # changed

print(f_outer(5)),

If f_inner() takes no argument?

May I generalize that the only use for closure is having a "closure factory"?

Thanks in advance :-)

Answer 1

I think you can find the answer here:
https://www.google.com/amp/s/proglib.io/p/kak-v-JUMP_LINK__&&__python__&&__JUMP_LINK-primenyayutsya-vlozhennye-funkcii-2021-02-09/amp/

Answer 2

You can use the translator built into the browser if you are using chrome

Answer 3

</CODER> It's in Russian :-) Didn't see language oprion in desktop mode but I'll look at the examples, thank you 😊

Answer 4

</CODER> Hehe no I try to stay away from unnervingly friendly, doublespeaking psychopathic cyclopses(google and derivatives and all other monopolies) on phone as much as I can but I'll definitely look it up when on pc, thanks for the tip.