About return values

Question

It seems like this code should print 1 because the function call rec(f); passes the value 1, it seems like it would ignore what's in variable i and have it replaced with the value of variable f.
But it prints 0 instead.
public class Program
{
public static void main(String[] args) {
int f=1;
int i=0;
rec(f);
System.out.println(i);
}
public static int rec(int i){
return i;
}
}

Answer 1

rec(f) returns f but you are not catching return value. To catch it, store in a variable like
i = rec(f);
Or print returned value by System.out.print( rec(f));

Answer 2

This is the correct way:
https://code.sololearn.com/cgGpAJ6sJ7zs/?ref=app

Answer 3

Thank you so much, I like both styles but this here seems very interesting, I've never seen it done like this:
//"System.out.println(rec(f));"
// but I forgot about doing it this
// way:
// i = rec(f);
public class Program
{
public static void main(String[] args) {
int f=1;
int i=0;
rec(f); //You need to initialize the returned value in i
System.out.println(rec(f));
}
public static int rec(int i){
return i;
}
}