Find the duplicate element in the given array

Question

Find the duplicate element in the given array. [1, 5, 2, 2, 3, 4, 3, 5, 2, 6, 7, 9, 8, 5]
Output:
2
3
5
I've tried with this but it only worked for 2 duplicate values. If it's 3 or 4 duplicate values then it won't work. Can you help me, please?
My Code:
int arr[] = {2,3,4,2,5,3,7,8,9,2,4};
Arrays.sort(arr);
for (int i = 0; i < arr.length; i++) {
for (int j = i + 1; j < arr.length; j++) {
if(arr[i] == arr[j]){
System.out.println(arr[i]);
}
}
}

Answer 1

Task is to print only dublicate elements..!!?
But What it means 3 or 4 dublicates?
Your code prints dublicates values only but the same in number of dublicates-1 times..
First by outer loop, print element if you found a dublicate, then skip next same dublicate elements.
So use a outer for loop for finding dublicate, if you find a dublicate then skip next elements by another loop innerly in if block like
if( ar[i] == ar[i+1] ) {
System.out.println(ar[i]) ;
while( i<ar.length && ar[i] == ar[i+1] )
i++;
}
I am checked code but hope it helps to correct it...