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# Can anyOne figure this out?

The snail climbs up 7 feet each day and slips back 2 feet each night. How many days will it take the snail to get out of a well with the given depth? Sample Input: 31 Sample Output: 6 Explanation: Let's break down the distance the snail covers each day: Day 1: 7-2=5 Day 2: 5+7-2=10 Day 3: 10+7-2=15 Day 4: 15+7-2=20 Day 5: 20+7-2=25 Day 6: 25+7=32 So, on Day 6 the snail will reach 32 feet and get out of the well at day, without slipping back that night

6/29/2022 2:44:47 PM

Abolfazl Abbaspour

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Abolfazl Abbaspour First take the input from user,Create a variable,Let's name it NoOfFeet, And Initialise it with 0 , Keep increasing it with 5 (7-2=5)Also keep noticing the number of iteration of the loop(By creating a variable and keep incrementing it in loop). If NoOfFeet>well depth, Then get out of loop. And the variable that you've created for noticing the number of iterations,Will be your answer.

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Yes, but what exactly do you need help with?

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It's giving you the math in the task description. You wrote it out.

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This is The Hint 👇🏻 Hint: You can use a loop to calculate the distance the snail covers each day, and break the loop when it reaches the desired distance.

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the Math 😅😁

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Justice ??

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the problem is i don’t know wrote what where Justice

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Intresting one ,What have you tried so far?

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nothing

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You can try this as well n is the input 7x - 2(x - 1) = n x = (n - 2) / 5 result -> x + (x % 5 != 0)

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i = 0; for (; depth > 0;) { i++; depth -= 7 if (depth > 0) { depth += 2 } } console.log(i);