Plz explain me, When we run the Code (Mentioned Below), We get Output as soft. Why?

Question

#include<stdio.h>
int main()
{
printf("s""o""f""t""\n");
return 0;
}

Answer 1

Quoted from https://en.cppreference.com/w/c/language/string_literal

"... at translation phase 6 (after macro expansion), the adjacent string literals (that is, string literals separated by
whitespace only) are concatenated."

Answer 2

Because that is what you typed for the program to do.

Note that "\n" is a character set that means New Line, so it will not be seen visual in the output.

Answer 3

Ipang Thanx Bro!

Answer 4

Justice Thanx!