Hi there please fix my answer😬

Question

This is question in python
No one likes homework, but your math teacher has given you an assignment to find the sum of the first N numbers.
Let’s save some time by creating a program to do the calculation for you!
Take a number N as input and output the sum of all numbers from 1 to N (including N).
Sample Input
100
Sample Output
5050
Explanation: The sum of all numbers from 1 to 100 is equal to 5050.
🍃🍃🍃
My answer is:
N = int(input())
#your code goes here
N= int(input())
S= ((N+1)*(N//2))
for i in rang(1,n+1):
print(S)
How can i fix??

Answer 1

Sharareh heyati ,
see some hints to get the code fixed:
N = int(input())
N= int(input()) # this is douplicated, remove it
S= ((N+1)*(N//2)) # this is the formula to calculate the sum, but i suppose you should learn it by using a loop. so remove it
S = 0 # we need to declare and initialize a variable that will hold the total
for i in rang(1,n+1): # spelling of n is not correct, spelling of rang is not correct
print(S) # not required indide the loop, remove it
S += i # add the numers of the range here
# finally print the result stored in S outside the loop here
print(S)

Answer 2

Is you are taking 2 times input? Why? It only have single input.
N*(N+1) //2 formula then you don't need loop. Just print this result.
Hope it helps..

Answer 3

N = int(input())
#your code goes here
sa = 0
for i in range(1, N+1):
sa += i
if (sa >= 100):
print(sa)
These code work 😬👌

Answer 4

Sharareh heyati Do what Jayakrishna🇮🇳 suggested and remove the if statement

Answer 5

In addition:
Check your indentation.
Check the spelling: it is "range"

Answer 6

Ok everyone
I try to fixed this Q like this but i have an error again☺
N = int(input())
#your code goes here
S= ((N+1)*(N//2))
s=1
for i in range(1, N+1):
s+=i
print(s)

Answer 7

By using loop now, you don't need to calculate S = (N+1) *N//2 remove it
Add identation for s+=I
N = int( input())
s=0 #set to 0, not 1
for i in range(1, N+1) :
s += i
print(s)

Answer 8

Again: Check the INDENTATION, indentation is crucial in Python.
S doesn't serve any purpose, remove it.
Set s = 0 in the beginning

Answer 9

Read the task description carefully: You always need to print the result, not only when sa >= 100.
Suppose N was 4. Then sa would be < 100 and the result would not be printed.

Answer 10

Yes thats true so what can i do😒

Answer 11

AGAIN: ⭐INDENTATION⭐ IS CRUCIAL IN PYTHON. Check your indentation.

Answer 12

Add statement like I added in my post. . Without space for print(sa) when without if.
edit:
Sharareh heyati
see this code for idenation, if you need
https://code.sololearn.com/cT5BRIbkia21/?ref=app

Answer 13

Thanks I do finally 😬👌
I had one space before print
So I removed it and ✔

Answer 14

https://code.sololearn.com/c2j0TUoL01oE/?ref=app
Easier code😄 (only 3 lines) using formula s=n(n+1)/2. I was thought to avoid loop whenever we can solve using arithmetic

Answer 15

I was interested in this task, so I rewrote your code here:›
##
en=int(input())
s=0
cou=0
while (en>=1):
s=s+en
en-=1
cou+=1
print(str(cou)+". "+str(s)+" + "+str(en)) #you can remove this line and change it to "print(s)" after "while", if you don't want to see all solution

Answer 16

#why you need if (sa>=100) : condition? its no output if input is less than 14.. You just need .
N = int(input())
sa = 0
for i in range(1, N+1):
sa += i
print(sa)

Answer 17

I do the Jayakrishna🇮🇳 suggeste but the print line have an error

Answer 18

Ok. Im going to ✔

Answer 19

U either use formula or add all the elements
To add the elements
initialize a variable as zero
add each element to the variable using a loop and print the sum atlast