why this code is not working?

Question

/*
Explanation:
itoa() takes the integer input value input and converts it to a number in base radix. The resulting number a sequence of base-radix digits.
Example: itoa() example */
#include<stdio.h>
#include<stdlib.h>
int main ()
{
int no;
char buff [50];
printf ("Enter number: ");
scanf ("%d",&no);
itoa(no,buff,10);
printf ("Decimal: %s\n",buff);
itoa(no,buff,2);
printf ("Binary: %s\n",buff);
itoa(no,buff,16);
printfp("Hexadecimal: %s\n",buff);
return 0;
}
https://code.sololearn.com/cqxi0gx7usKR/?ref=app

Answer 1

itoa() is non-standard function, you can't be sure about its availability in various systems
https://www.cplusplus.com/reference/cstdlib/itoa/
https://stackoverflow.com/questions/190229/where-is-the-itoa-function-in-linux

Answer 2

Ur-Wellwisher You can use ssprintf() as an alternative to itoa().