Prime Number | if n=4, answer=87 Calculation will be like this 2*2+3*3+5*5+7*7 if n=5, answer=208 2*2+3*3+5*5+7*7+11*11

Question

for Number in range (1, 101):
count = 0
for i in range(2, (Number//2 + 1)):
if(Number % i == 0):
count = count + 1
break
if (count == 0 and Number != 1):
print(Number)
This is the prime number in range but how to implement this if n=4, answer=87 Calculation will be like this 2*2+3*3+5*5+7*7 if n=5, answer=208 2*2+3*3+5*5+7*7+11*11.
Any ideas
Thanks.

Answer 1

Manoj Bhaagam
May I suggest the following option. I was intrigued with the concept.
from sympy import primerange as pr
primes = list(pr(1,100)) #primelist
n = int(input())
total =0
for i in range(n):
total += primes[i]**2
print(total)

Answer 2

You can make a function with a parameter n,
<del>
use "n*2+1" as the second argument of the first range()
</del>
store the square of each number in a list, and return the sum.
edit: wait... i did it but something still doesn't work quite right... it only works with n=4 haha
2nd edit: I made a new attempt with a "while" loop, it only works with 1 and 2, when you put 3, the loop becomes infinite wtf 😆 weird things are happening here
3rd edit: the problem was a "Tab" I deleted it and it works, so the solution is this, change the first for to a while that compares n with len() of the list, Initialize Numbers before the while, and inside the loop you add 1 to it. This added to what I already said at the beginning of this message.
Anyway, thanks for the practice, I had fun for a while haha
https://code.sololearn.com/ccLYDN2f785U/?ref=app

Answer 3

Per Bratthammar thank you

Answer 4

Cristian Gabriel Mazzulla 😇

Answer 5

Hi! Here’s one solution:
https://code.sololearn.com/cX8Ag1XwIq0S/?ref=app

Answer 6

Manoj Bhaagam Hi! Is it:
2**2 + 3**2 + 5**2 +… + n**2
or
2**2 + 3**3 +5**5 +… + n**n
It is hard to tell from your description. However, its easy to adjust my code to get it as you want. /p 🙂

Answer 7

Per Bratthammar 2nd one n*n