Can not pass internal test. In to variance range.

Question

Hello everyone, dear friends, I need a help below text of task and my code.
Text of task:
The given code includes a list of heights for various basketball players.
You need to calculate and output how many players are in the range of one standard deviation from the mean.
My code:
players = [180, 172, 178, 185, 190, 195, 192, 200, 210, 190]
count = 0
accum = 0
variance = 0
new_players = []
for i in players:
count = count + 1
accum = accum + i
mean = accum / count
for j in players:
variance = variance + (mean - j)**2
variance = (variance/count)**1/2
min_value = mean - variance
max_value = mean + variance
for i in players:
if i > min_value and i < max_value:
new_players.append(i)
print(len(new_players))

Answer 1

variance = (variance/count)**1/2 is similar to ((variance/count)**1)/2 = (variance/count)/2
Try doing this instead
variance = (variance/count)**(1/2)

Answer 2

Lyapunov Alexander
Just a tip:
python has a sum() function.
mean = sum(players) / len(players)

Answer 3

Simba
Thank you, yes... **(1/2) is correct decision!

Answer 4

Denise Roßberg
Okay, great. It is very useful tip ;-)