Whats wrong with this code?

Question

I want to create a function which give me a list with all numbers smaller than the entered one if they are divisible by 3 and 5. But I don't get the output I want. Any hints? Thanks!
num = int(input())
list=[]
def all_smaller_num(x):
while x > 0:
x -= 1
if (x % 3 == 0) and (x % 5 == 0):
list.append(x-1)
return list
all_smaller_num(num)
print(list)

Answer 1

Your return statement is in if block so on first append() , control goes back to calling statement. Returns from function. So remove from loop and at end of function.

Answer 2

You don't need to return the `list`, it's on global scope already. Unless you assign the return value to something (e.g. a variable), or pass it to a function (as argument), there's no necessity to issue a `return`.
You can still opt to define the list inside the function though, that way it makes sense to issue a return.

Answer 3

#A number fully divisible by both 3 and 5 is also a number fully divisible by 15. So it might worth considering to use two while...loops to accomplish this more efficiently.
#The first while...loop searches for a number that is less than <x> and be fully divisible by 15. The second while...looo adds the matching numbers to the list.
def all_smaller_num(x):
# find first number fully divisible by 15
while x > 14 and x % 15:
x -= 1
# add matching numbers to <lst>
lst = []
while x > 14:
lst.append(x)
x -= 15
return lst
print( all_smaller_num( 1000 ) )

Answer 4

You could eliminate the loops and the filtering of unwanted values. Simply generate the values you want by using range. Look:
num = int(input())
a = list(range(3, num+1, 3)) + list(range(5, num+1, 5))
a = list(set(a))
print(a)

Answer 5

num = int(input())
list=[]
def all_smaller_num(x):
while x > 0:
x -= 1
if (x % 3 == 0) and (x % 5 == 0):
list.append(x-1) #Why x-1 here?
return list
all_smaller_num(num)
print(list)

Answer 6

Oh yes, that makes no sense indeed. I thought it would be necessary to append the next smaller integer to the list, but this should execute by the x-=1, right?
But nevertheless: when I change the x-1 to x I still get only on number in the list as output :-(

Answer 7

And please avoid using any of the built-in class name for variable names. You may accidentally shadow and override the built-in class definition.

Answer 8

ah I just realized, it is returning the list in the first match. return must go outside the loop

Answer 9

Oh yes, now it works! Thank you both for your help! From now on I will remember for ever: return outside the loop and in one level with the function!

Answer 10

Omit the (x-1). It should be done. The code should look like this:
num = int(input())
list=[]
def all_smaller_num(x):
while x > 0:
x -= 1
if (x % 3 == 0) and (x % 5 == 0):
list.append(x)
return list
all_smaller_num(num)
print(list)
\*Please correct me if I'm wrong, appreciated it. Thanks! */

Answer 11

Example: number_of_likes = int(input())

Answer 12

def FN (ins):
a = False
n = 2;
while (not a):
um = set ( []) for i,item in enumerate (ins): ni = item/n if(ni not in um):
else:
break
つく
um.add(ni) if(i==len (ins)): a = True
4
if not a:
5 V
6
n =n+1
7
8
return n
9
20 if
__name__ == '_ _main__':
21
22
inp = list (map (int, input().rstrip().split() n = inp.pop(0)
23
24
ar = inp print (FN (ar))
Test Results
Custom

Answer 13

link your actual code. it is easier for you and the people trying to help.

Answer 14

Hello