open files in python

Question

Hello everyone, I am learning the python core courses, and in exceptions and files, I don't understand,
do somebody can help me.
(I am french, if a french see this)
thanks

Answer 1

create empty file :
f = open("myfile.txt", "a")
And
also Create a new file if it does not exist:
f = open("myfile.txt", "w")

Answer 2

You can create empty file :
f = open("myfile.txt", "x")
And also Create a new file if it does not exist:
f = open("myfile.txt", "w")

Answer 3

for those of you, who are interested in reading some more informations about the file open modes:
https://www.delftstack.com/howto/JUMP_LINK__&&__python__&&__JUMP_LINK/python-open-modes/

Answer 4

The Most Reliable Way To Open Files In Python File Handling Methods:
with open('filename.txt', 'w+') as read_write:
# Your Code Here...
read_write.close()

Answer 5

АлКа Релова You Can Run This Keyword For Help With File Handling...
>>help(open)

Answer 6

АлКа Релова also look at "with" statement to work with files

Answer 7

You can use try-except-finally block:
try:
file = open(filePath, 'w')
file.write("Hello World!")
except IOError:
print("Unable to create file on disk.")
finally:
file.close()

Answer 8

Can you send your task? I might suggest something then

Answer 9

I want a code

Answer 10

Pavan Kumar Code for "with" statement to work with file:
with open("test.txt",'w') as f:
f.write("Test file created.\n")
f.write("Some text written.\n")

Answer 11

It's recommended to close the file after using it.
f = open("demofile.txt", "r")
# some code
f.close()

Answer 12

Yes but i don't understand how to create a file ??

Answer 13

Thanks
And in the course, it is written that he must be in the same file of the code
(Sorry i don't speak english very well)

Answer 14

Mathéo
You Can Even Link Files In Different Directories!

Answer 15

Just do like this for open file
f = open("python.txt,"r)

Answer 16

You're best bet is to use a context manager to open the file (ex. The 'with'). That would be similar to an example in the comments.
with open("file.txt", 'r') as f:
#your code
You don't have to close the file with this method either because it's being used in a context manager and when the code you right finishes executing it will close the file for you.
You can also use context managers for other things as well, such as sockets.

Answer 17

#your code goes here
weight=int(input())
height=float(input())
if weight//height**2<18.5:
print("Underweight")
if weight//height**2<25:
print("Normal")
if weight//height**2<30:
print("Over weight")
if weight//height**2==30:
print("Obesity")
SAMPLE INPUT=85
1.9
SAMPLE OUTPUT=Normal

Answer 18

I want code