You are in charge of security at a casino, and there is a thief who is trying to steal the casino's money! Look over the security diagrams to make sure that you always have a guard between the thief and the money!
There is one money location, one thief, and any number of guards on each floor of the casino.
Task:
Evaluate a given floor of the casino to determine if there is a guard between the money and the thief, if there is not, you will sound an alarm.
My Solution:
n = input()
c = ""
for i in n:
if i != 'x':
c = c + i
a = c.index("G")
b = c.index("$")
c = c.index("T")
if b >= a and c >= b:
print("quiet")
elif a < b:
print("ALARM")
elif b < a and b < c:
print("quiet")
else:
print("ALARM")
#Unable to pass only one test case :(
#I think, this works..
#Observe the condition for guard just..
n = input()
c = ""
for i in n:
if i != 'x':
c = c + i
a=0
for i in c:
if i == 'G':
a = a + 1
#a = c.index("G")
b = c.index("$")
c = c.index("T")
if (b>a>c) or (b<a<c): #a between b and c(, guard between $ and T
print("quiet")
else:
print("ALARM")
#may this can be simplified in many ways in python.. but to understand problem, these steps clear that I hope.
**never give up in trying to solve anything..
hope it helps....
ANOTHER IDEA
REMOVE UNNECESSARY X AND CHECK IF THIEF IS BESIDE MONEY OR NOT
a=input().replace('x','')
if a.index('T') in [a.index('$')+1,a.index('$')-1]:
print('ALARM')
else:
print('quiet')
x = ''.join(input().split('x'))
y = ''.join(x.split('T$'))
z = ''.join(y.split('$T'))
print('ALARM'if '$' not in z else 'quiet')
Noob style: passes all tests.
#x removes space.
#y&z remove only the thieves with money
#If money is gone an alarm
#else - it's all quiet
i = list(input())
x = []
for r in range(len(i)):
if i[r] != "x":
x.append(i[r])
z = "".join(x)
if "$T" in z or "T$" in z:
print("ALARM")
else:
print("quiet")
or:
i = input().replace("x", "")
if "$T" in i or "T$" in i:
print("ALARM")
else:
print("quiet")
