why this code still runs as space is insufficient in malloc in c....???

Question

#include<stdio.h>
#include<stdlib.h>
int main(){
int *x;
x=(int*)malloc(1);
for(int i=0;i<9;i++){
x[i]=i+10;
if (x!=NULL){
*(x+2)=50;}
printf("%d\n",x[i]);
}
return 0;
}

Answer 1

It seems to mess up whatever comes in first from stdin. Then gives x 8 bytes of data and continues.
https://code.sololearn.com/cyjdlkx88aDn/?ref=app