Why Scanf is not run properly ?

Question

#include<stdio.h>
void Bubble_Sort(char A[],int size)
{
int i,round;
char temp;
for(round=0;round<size;round++)
{
for(i=0;i<round-1;i++)
{
if(A[i]>A[i+1])
{
temp=A[i];
A[i]=A[i+1];
A[i+1]=temp;
}
}
}
for(i=0;i<size;i++)
{
printf("%c\t",A[i]);
}
}
main()
{
char A[100];
int i,size;
printf("\nEnter Your Size Of Array");
scanf("%d",&size);
for(i=0;i<size;i++)
{
scanf("%c",&A[i]);
}
Bubble_Sort(A,size);
}

Answer 1

It probably doesn't run right because when you scan for characters, spaces and new line characters ALSO count as characters. They're stored but not visible. Look at the spaces i give in the call to scanf(" %c ", &A[i]);

Answer 2

works fine here w/ chars. idk what you're trying to do
//input:
3 a b c
//output:
Size: 3
Array values: a b c
https://code.sololearn.com/cgkjdo6n7Mk4/?ref=app

Answer 3

Yeah, you'll have to look through my codes and make some changes for yourself though. Mine works fine, probably because i sort and display in different functions. If they are in functions at all

Answer 4

I just changed all the character variables to integer variables and made it scan for integers.
//input:
3 2 1 3
//output:
Size: 3
Array values: 1 2 3
https://code.sololearn.com/cLC12UjYhYL1/?ref=app

Answer 5

If we use char type value
Why Scanf is not run properly?

Answer 6

Input = 3 b d a
Output = a b d
i am thinking to do this !
can you do ??