1 Answer
New AnswerI think this problem in 4 DAYS and i cant find any way to fix this problem Using char array There is my code: https://code.sololearn.com/cpNxt5vUSpYV/?ref=app
7/22/2021 11:58:14 AM
Global Long
1 Answer
New AnswerReplace: if(pos[i][0] == pos[i][1] && pos[i][1] == pos[i][2] || pos[0][j] == pos[1][j] && pos[1][j] == pos[2][j] || pos[0][0] == pos[1][1] && pos[1][1] == pos[2][2] || pos[0][2] == pos[1][1] && pos[1][1] == pos[2][0]) { Win = true; } With : if(((pos[i][0] == pos[i][1]) && (pos[i][1] == pos[i][2])) || ((pos[0][j] == pos[1][j]) && (pos[1][j] == pos[2][j])) || ((pos[0][0] == pos[1][1]) && (pos[1][1] == pos[2][2])) || ((pos[0][2] == pos[1][1]) && (pos[1][1] == pos[2][0]))) { Win = true; } }
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