Sequence numbering Python 3

Question

If i wamt to output 1.
2.
3.
But don't want to keep writing each number..os there a way to make it faster ?

Answer 1

Amer ,
range can take 3 arguments:
range(<start number>, <end number ( not including )>, <step>)
see what this code is resulting:
for num in range(5, 11):
print(num)
'''
result is:
5
6
7
8
9
10
'''

Answer 2

if u use a wild range of numbers
for n in [1,4,7,9,74]:
print(f"{n}. ")

Answer 3

for n in range (x):
print(n)
----
This will print all integers from 0 to x.

Answer 4

.... Simons solution but
print(f"{n}.")

Answer 5

for n in range(5, 11):
if n != 7:
print(n)

Answer 6

Amer ,
i don't know what language you are going to, but you ca do it with a loop. you may need to get an input to define the max number to output.
the numbers itself can be generated by a range or with a variable that will be incremented in each loop iteration.
the dot after the number can be added during print output.
happy coding and good success!

Answer 7

Thanks guys it worked.
One more thing
Say i want to exclude 0..or make the range from 5 to 15 for example. How would it go.

Answer 8

Amer it works!
Oma Falk just forgot the colon at the end of the first line ...

Answer 9

I'm learning python 3
Could you please assist me with an example ?

Answer 10

Perfect.
Say i want to exclude 7 from that range you resulted.
So 5 6 8 9 10
Last question i swear 😆

Answer 11

Thanks alot guys

Answer 12

This one gave error

Answer 13

Works..thanks folks!