If condition with and operator in loop

Question

Is below code not supposed to work. I wanted to print both the words using if condition from the list. Works fine with or operator.
words = ["hello", "world", "spam", "eggs"]
for word in words:
if word == 'hello' and word == 'eggs':
print(word + "!")
break

Answer 1

Your if-condition implies that 'word' is equal to "hello" AND 'word' is equal to "eggs". Any string can't be equal to "hello" and "eggs" at the same time. So the condition is never true and the code inside the if-block is never executed.

Answer 2

word == 'hello' and word == 'eggs' is impossible.
x% 2== 1 and x > 4 is possible.
What exactly do you want your code to do?

Answer 3

Is your expected output
hello!
eggs!
?
If so, you have to use 'or'.
'and' doesn't make sense.

Answer 4

Ok. Thanks a lot guys 🙂

Answer 5

But in below example by Sololearn there are 2 values that can be taken by x (5 and 7) and only 1 is printed because of break statement. Also, what to do if I want to print any 2 specific words out of these 4 in the list in my above example.
list = [2, 3, 4, 5, 6, 7]
for x in list:
if ( x% 2== 1 and x > 4):
print (x)
break

Answer 6

Ok. Just wanted to check if words I specified were in the list and print them.