array element removal

Question

void remove(float a[], int& n, int i);
void read(float a[],int& n);
void print(float a[],int& n);
const int MAXSIZE=100;
int main()
{
float a[MAXSIZE],element;
int size;
read(a,size);
cout<<"the array is: ";
print(a,size);
cout<<"\nThe value you want to remove: ";
cin>>element;
remove(a,size,element);
}
void read(float a[],int& n)
{
n=0;
do
{
cout<<"a["<<n<<"]="<<endl;
cin>>a[n];
}
while(a[n++]!=0 && n<MAXSIZE);
--n;
}
void print(float a[],int& n)
{
for(int i=0; i<n; i++)
{
cout<<a[i]<<",";
}
}
void remove(float a[], int& n, int i)
{
for (int j=i+1; j<n; j++)
{
a[j-1] = a[j];
--n;
}
}
the code runs but after taking the array as input, the value I want to remove that part doesn't execute.What is the problem?

Answer 1

Input:
5
10
20
30
40
50
30
#include <iostream>
using namespace std;
void remove(float a[], int& n, int i);
void read(float a[],int& n);
void print(float a[],int& n);
const int MAXSIZE=100;
int main() {
float a[MAXSIZE],element;
int size;
cin >> size;
read(a,size);
cout<<"the array is: ";
print(a,size);
cout<<"\nThe value you want to remove: ";
cin>>element;
cout<<element<<endl;
remove(a,size,element)
int new_size = size-1;
print(a, new_size);
}
void read(float a[],int& n) {
for(int i = 0; i < n; i++){
cout<<"a["<<i<<"]="<<endl;
cin>>a[i];
}
}
void print(float a[],int& n) {
for(int i=0; i<n; i++)
cout<<a[i]<<",";
}
void remove(float a[], int& n, int i) {
for (int j=0; j<n; j++) {
if(a[j]==i){
for(int k=j; k<n-1; k++)
a[k] = a[k+1];
break;
}
}
}

Answer 2

I might be wrong but where did you declare I for the remove function? The only place I can see you have declared it is in a different function but variables don't transfer between functions
That is probably your error because the for loop won't work

Answer 3

Thank you all very much for helping. I am just learning even though I don't like coding but I have to because I have this c++ course in this running semester.