Java 16.2

Question

I need help :)
import java.util.Scanner;
public class Main {
public static void main(String[] args) {
Scanner read = new Scanner(System.in);
int number = read.nextInt();
while (3<number){
number--;
if((number%3==0) && (number!=0)){
System.out.println(number);
}
}
}
}

Answer 1

You mean in reverse order?

Answer 2

Else the values you are getting store it in empty string

Answer 3

Try to do by yourself first

Answer 4

import java.util.Scanner;
public class Main {
public static void main(String[] args) {
Scanner read = new Scanner(System.in);
int number = read.nextInt();
int i=3;
while (i<number){
if(i%3==0 || i%10==3){
System.out.println(i);
}
i++;
}
}
}
//Check out for this

Answer 5

To make task 4 work too, add "=". Namely, in the condition "while"
while (i <= number)

Answer 6

What help do you want the program is working fine?

Answer 7

The weird client loves the number 3 and wants you to write a program that prints out all numbers from 1 of the entered number that are either multiples of 3 or end in 3.
Sample input
14
Result example
3
6
9
12
13

Answer 8

Ok just check for multiple of 3 and check if the remainder of the number is 3 or not that's all

Answer 9

I can't print a number with a 3 at the end

Answer 10

I did the opposite

Answer 11

My result is 13-3

Answer 12

Then store 3 in a variable and after the condition increase in by 1

Answer 13

import java.util.Scanner;
public class Main {
public static void main(String[] args) {
Scanner read = new Scanner(System.in);
int number = read.nextInt();
int n=3;
if(number>n)
{
while(n<=number)
{
if(n%3==0 || n%10==3)
System.out.println(n);
n++;
}
}
}
}

Answer 14

But task 4 wrong and closed

Answer 15

Hope this helps you

Answer 16

This task done !) thank you !)

Answer 17

My pleasure

Answer 18

Just use this to do it if(number%3==0 || number%10==3)

Answer 19

I must get 3-13

Answer 20

Tell me about please “if(number%3==0 || number%10==3)”, i dont understand