Why the below C code is not running properly?

Question

//Matrix multiplication
#include <stdio.h>
#include <conio.h>
int main()
{
int a[10][10],B[10][10],C[10][10],i,j,k,sum,m,n,p,q;
sum=0;
//clrscr();
printf("enter the size of matrix (row*column) A\n");
scanf("%d%d",&m,&n);
printf("enter the size of matrix (row*column) B\n");
scanf("%d%d",&p,&q);
if(n!=p)
{
printf("\nmultiplication is not possible");
}
else
{
printf("\nenter elements for matrix A:\n");
for(i=0;i<m;i++);
{
for(j=0;j<n;j++);
{
printf("\nelement A[%d][%d]=",i,j);
scanf("%d",&a[i][j]);
}
}
printf("\nenter elements for matrix B:\n");
for(i=0;i<p;i++);
{
for(j=0;j<q;j++);
{
printf("\nelement B[%d][%d]=",i+1,j+1);
scanf("%d",&B[i][j]);
}
}
//now multiplication
for(i=0;i<m;i++);
{
for(j=0;j<q;j++);
{
sum=0;
for(k=0;k<p;k++)
{
sum=sum+a[i][k]*B[k][j];
C[i][j]=sum;
}
}
}
//printing result
for(i=0;i<m;i++);
{
for(j=0;j<q;j++);
{
printf("%d\t",C[i][j]);
}
printf("\n");
}
return 0;
}}

Answer 1

Almost all of your *for* loops are doing nothing as you have terminated them with a semicolon .
Also <conio.h> is a non standard header and is not supported by most of the modern standard compilers.

Answer 2

Arsenic 👍

Answer 3

Check the syntax

Answer 4

Do not use semicolon after for loop.