Python

Question

Ребята, помогите решить задачу ☹️ Вообще не понимаю с чего начинать...
вот условия задачи:
Напишите программу которая проверяет кипит ли вода.
Получите температуру в качестве ввода (по шкале Цельсия) и выведите "Boiling" если температура выше или ровна 100.
Пример входных данных:
105
Пример выходных данных:
Boiling

Answer 1

This could work:
temperature = int(input())
if temperature >= 100:
print('Boiling')
else:
print('Not boiling')

Answer 2

Temperature = int(input())
If temperature >= 100:
Print(“boiling”)
Else:
Print (“not boiling”)

Answer 3

temperature = int(input())
If temperature >= 100:
Print ("boiling")
else:
Print("not boiling")

Answer 4

Rakesh, Print(with capital P) doesn't exist in Python but otherwise your answer is almost an exact copy of mine from a month earlier.

Answer 5

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Answer 6

THE ANSWER FOR YOUR CODE IS :-
Temp=(int(input()))
if temp >= 100:
print(Not Boiling)
else:
print( Boiling )

Answer 7

Конечно, вот простая программа на Python для решения вашей задачи:
```python
# Получаем температуру в качестве ввода от пользователя
temperature = float(input("Введите температуру в градусах Цельсия: "))
# Проверяем условие
if temperature >= 100:
print("Boiling")
else:
print("Not Boiling")
```
Эта программа запрашивает у пользователя ввод температуры в градусах Цельсия, затем проверяет, является ли введенная температура выше или равной 100. В зависимости от результата выводится соответствующее сообщение.

Answer 8

Спасибо 👍 помог очень!

Answer 9

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Answer 10

u are all benders

Answer 11

Solution to the problem.
def boiling(temp: int) -> str:
return "Boiling" if temp >= 100 else "Not boiling"
print(boiling(int(input())))

Answer 12

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Answer 13

I don't understand ur language

Answer 14

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savings = input()
# Convierte la entrada del usuario en un valor decimal y actualiza la variable
savings =
# Los ahorros crecen después de 1 año con ñuna tasa de interés anual del 5%
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# Muestra el mensaje

Answer 15

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