 How lst = [float(x) if x != 'nan' else np.NaN for x in input().split()] works | Sololearn: Learn to code for FREE!

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# How lst = [float(x) if x != 'nan' else np.NaN for x in input().split()] works

Hello, i wanna ask about something I wanna know how this code works, it actually has been used for lots of question in datascience project in sololearn lst = [float(x) if x != 'nan' else np.NaN for x in input().split()] One of the full code example down here :. Import numpy as np Import pandas as pd lst = [float(x) if x != 'nan' else np.NaN for x in input().split()] lst_df = pd.Series(lst) Sylv = lst_df.fillna(lst_df.mean()).round(1) print(Sylv)

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lst = [float(x) if x != 'nan' else np.NaN for x in input().split()] Its generator And equal this: lst =[] For x in input().split(): if x =! 'nan': lst.append(float(x)) else: lst.append(np.NaN)

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list comprehension: https://www.sololearn.com/learning/2454/ cant post a link that works so look for it in python tutorial

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input().split() its splitted into list input from user (by spaces in default)

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if on input u have "2 1 3 nan" on output u will have [2.0, 1.0, 3.0, NaN]

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Илья Мирошник Thank you xD, it helps lot