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Trying to solve library management in python core

Know am missing something but can seem to remember books = { "Life of Pi": "Adventure Fiction", "The Three Musketeers": "Historical Adventure", "Watchmen": "Comics", "Bird Box": "Horror", "Harry Potter":"Fantasy Fiction", "Good Omens": "Comedy" } book = input() #your code goes here if book not in books: print("Not found")

4/8/2021 12:46:10 PM

Simisola Osinowo

9 Answers

New Answer

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i think since its a dictionary, you could compare input to the dictionary keys instead of the key:value pairs. if found, you'd need to access the dictionary by using the key and print out its genre value.

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if book in books: print(books[book])

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it works like this : books = { "Life of Pi": "Adventure Fiction", "The Three Musketeers": "Historical Adventure", "Watchmen": "Comics", "Bird Box": "Horror", "Harry Potter":"Fantasy Fiction", "Good Omens": "Comedy" } book = input() if book in books: print(books[book]) #your code goes here else :

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book = input() try: print(books[book]) except: print("Not found")

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A library management program has a dictionary of books with their corresponding genres. Take a book name as input and output the genre.

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This might help: print(books.get(input(), "Not found"))

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for i in books: if i==book: print(books[i]) break else: print("Not found")

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When the problem is asking to use the .get() method instead of if/else, I used: print(books.get(book, "Book not found"))