Python search engine

Question

Guys Anybody know how write this!!
You’re working on a search engine. Watch your back Google!
The given code takes a text and a word as input and passes them to a function called search().
The search() function should return "Word found" if the word is present in the text, or "Word not found", if it’s not.
Sample Input
"This is awesome"
"awesome"
Sample Output
Word found

Answer 1

Why is using return mandatory, but not directly using print("Word Not Found")?

Answer 2

Emre Sarıcan
You need to check word in text but you didn't.
Solution:-
#That is mine try
text = input()
word = input()
def search(text, word):
#for i in word:
if word in text:
a ="Word found"
return a
else:
b = "Word not found"
return b
print(search(text, word))

Answer 3

def search(text,word):
if word in text:
print("Word found")
else:
print("Word not found")
return (search)
text = input()
word = input()
search(text, word)
This worked for me try it out.

Answer 4

There are two problems
1 - Indentation
2 - you are taking input as word but passed in function as Word.
So try this
text = input()
word = input()
def search(text, word):
if word in text:
print("Word found")
else:
print("Word not found")
search(text, word)

Answer 5

def seacrh(text,word) :
if word in text :
print ('Word found')
else:
print('Word not found')
text = input()
word = input()
seacrh(text,word)
done..!

Answer 6

Emre Sarıcan
One more thing you should always call function after declaration otherwise you will get error.

Answer 7

I understood thank you for all

Answer 8

Emre Sarıcan
Most welcome 🙂
Happy coding 👍

Answer 9

text = input()
word = input()
def search(text, word)
if word in text:
print("Word found")
else:
print("Word not found")
print(search(text, word))
Important points to note: Always declare variables before creating function

Answer 10

#Here is my code try it:
def seacrh(text,word) :
if word in text :
print ('Word found')
else:
print('Word not found')
text = input()
word = input()
seacrh(text,word)

Answer 11

I still cant get it

Answer 12

text = input()
word = input()
def search(text,word):
if word in text:
print("Word found")
else:
print("Word not found")
search(text, word)

Answer 13

you can use this code
text = input()
word = input()
def search(text, word):
if word in text:
a = "Word found"
return a
else :
a = "Word not found"
return a
print(search(text, word))

Answer 14

https://code.sololearn.com/WBVBiXD0Su77/?ref=app
Here, working

Answer 15

text = input()
Word = input()
def Search(text,word):
if word in text:
a = "Word found"
return à
else
b = "Word not found"
return b
print(search(text, word))

Answer 16

text = input()
word = input()
def search(text, word):
if word in text:
print("Word found")
else:
print("Word not found")
search(text, word) #just remove the print, by me :D

Answer 17

https://code.sololearn.com/WZtea7XgCOpa/?ref=app

Answer 18

Emre Sarıcan
Here is my code try it:
def seacrh(text,word) :
if word in text :
print ('Word found')
else:
print('Word not found')
text = input()
word = input()
seacrh(text,word)

Answer 19

Thank youi

Answer 20

That is mine try
text = input()
word = input()
print(search(text, word))
def search():
for i in word:
if i == word:
a ="Word found"
return a
else:
b = "Word not found"
return b